getArchiveFileName

@Internal(value = "Represented as part of archiveFile")
open fun getArchiveFileName(): Property<String>(source)

Returns the archive name. If the name has not been explicitly set, the pattern for the name is: [archiveBaseName]-[archiveAppendix]-[archiveVersion]-[archiveClassifier].[archiveExtension]

Return

the archive name.

Since

5.1